Question

In triangle ABC , AD is the median and DE is parallel to BA .Prove that BE is also a median.

Answer 1

Since AD is the median of ΔABC, then BD = DC.

Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,

it bisects the third side which in this case is AC at E.

Therefore, E is the mid point of AC.

Hence, BE is the median of ΔABC.

Answer 2

Answer:

e is the midpoint .hope it helps