In triangle ABC , AD is the median and DE is parallel to BA .Prove that BE is also a median.
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Answered by
17
Since AD is the median of ΔABC, then BD = DC.
Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,
it bisects the third side which in this case is AC at E.
Therefore, E is the mid point of AC.
Hence, BE is the median of ΔABC.
Hope this helps you !!
Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,
it bisects the third side which in this case is AC at E.
Therefore, E is the mid point of AC.
Hence, BE is the median of ΔABC.
Hope this helps you !!
Answered by
6
from the above picture
ABC is a triangle. d is the median .and de is parallel to ba.and be is also a median.
that's the answer.
please mark it as brainliest
ABC is a triangle. d is the median .and de is parallel to ba.and be is also a median.
that's the answer.
please mark it as brainliest
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