Question

In triangle ABC, AD is the median.

Prove that AB+BC+AC> 2 AD​

Answer 1

Step-by-step explanation:

Given, △ABC, AD is median of triangle, on side BC

Now, In △ABD,

AB+BD>AD (Sum of two sides of triangle is greater than the third side)

Now, In △ACD,

AC+CD>AD (Sum of two sides of triangle is greater than the third side)

Thus, adding both,

AB+BD+AC+CD>2AD

AB+AC+BC>2AD

hence proved

HOPE THIS HELPS YOU

Answer 2

Answer:

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