Question

in triangle ABC,AD is the median. show that AB + BC+ AC> 2 AD​

Answer 1

Answer:

AB+BD+AC+CD>2AD

AB+AC+BC>2AD

Step-by-step explanation:

Given, △ABC, AD is the median of a triangle, on side BC

Now, In △ABD,

AB+BD>AD (Sum of two sides of a triangle is greater than the third side)

Now, In △ACD,

AC+CD>AD (Sum of two sides of a triangle is greater than the third side)

Thus, adding both,

AB+BD+AC+CD>2AD

AB+AC+BC>2AD