In triangle ABC, AD is the perpendicular bisector of BC. show that triangleABC is an isosceles triangle in which AB=AC.
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Step-by-step explanation:
1.) in the triangle ABC let AD be the perpendicular Bisector of line BC making an angle of 90 degree on the line BC.
2.) in triangle ABD and ACD
AD=AD (common line)
angle ADC = angle ADC (given 90 degree)
BD=DC (given Bisector)
hence by SAS similarity Triangle ABD= ADC
therefore: Side AB = side AC (CPST)
since the opposite two sides are equal therefore triangle ABC is an Isosceles triangle.
Hence proved!
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