in triangle ABC, AD perpendicular to BC and AB = AC then prove that tringle ABD congruent to ACD
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Answer: mark the brainliest
Step-by-step explanation:
In △ADB and △ADC
AB=AC (given)
AD=AD (common side)
∠ADB=∠ADC=90
∘
(As AD⊥BC)
∴△ADB≅△ADC by RHS property.
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