In triangle ABC and PQR, AB/PQ = AC/PR =AD/PM where AD and PM are corresponding medians. Prove that the triangles are similar.
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acc to the propertionality theorem;
if AB/PQ=AC/PR=AD/PM;
AB=PQ
AC=PR
therefore by SS test...triangle ABC=triangle PQR
if AB/PQ=AC/PR=AD/PM;
AB=PQ
AC=PR
therefore by SS test...triangle ABC=triangle PQR
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AB/PQ = BC/QR = AC/PR
Therefore AB/PQ = BC/QR = AC/PR = AD/PM (Corresponding sides are proportional, since they are similar triangles)
Therefore AB/PQ = AD/PM
Therefore AB/PQ = BC/QR = AC/PR = AD/PM (Corresponding sides are proportional, since they are similar triangles)
Therefore AB/PQ = AD/PM
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