in triangle abc and triangle adc are two right angled triangles on the same base ac with angle b = 90° . also ad||bc . prove that ab = cd and ab||cd
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In triangle abc and triangle dac
<bac=<dca (alt.angles)
<bca=<dac (alt.angles)
ac=ac (common)
therefore,triangle abc and adc congruent proved by aas
therefore,triangle abc and triangle dac is congruent proved by cpctc
thus,ab=cd since triagle abc and triangle dac is congruent(already proved)
and ab||cd since <bac=<dca & <bca =<dac
<bac=<dca (alt.angles)
<bca=<dac (alt.angles)
ac=ac (common)
therefore,triangle abc and adc congruent proved by aas
therefore,triangle abc and triangle dac is congruent proved by cpctc
thus,ab=cd since triagle abc and triangle dac is congruent(already proved)
and ab||cd since <bac=<dca & <bca =<dac
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