Question

In triangle ABC and triangle DEF .if AB is equal to FD and angleA is equal to angle D. write the third condition for which two Triangles are congruent by SAS congruence rule.

Answer 1

in triangle ABC And triangle DEF
AB = FD Given
angle A = angle D
AC = DE given
u can take -
BC = EF given
therefore triangle ABC = triangle DEF By sas rule

Answer 2

Given:

In triangle ABC and triangle DEF

A B=FD

Angle A=Angle D

To find:

Third condition for which two triangles are congruent by SAS rule

Solution:

In triangle ABC and triangle DEF

AB=FD (Given)

Angle A=Angle D  (Given)

AC=DE

$\triangle ABC\cong \triangle$ DEF

By SAS postulate

Therefore, the third condition is

Side AC=Side DE