in triangle ABC and triangle EDC AB is parallel to ED . BD =1/3BC and AB =12.3 cm prove that triangle ABC ~Triangle EDC.
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Answered by
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first prove an one pair of alternate angle and then taking angle c as common angle , the triangles are proved similar by AA TEST
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33
1.
giving in question:- AB||ED
AngelB=AngelD and AngelA=AngelE
AE/AC=BD/BC=ED/AB
And AAA TEST.
2.
if BD/BC=ED/BA
BD=1/3BC=ED/12.6
4.1BC=BC×ED
4.1BC/BC=ED
4.1=lED
3.only two next time i help.
giving in question:- AB||ED
AngelB=AngelD and AngelA=AngelE
AE/AC=BD/BC=ED/AB
And AAA TEST.
2.
if BD/BC=ED/BA
BD=1/3BC=ED/12.6
4.1BC=BC×ED
4.1BC/BC=ED
4.1=lED
3.only two next time i help.
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