Question

in triangle ABC and triangle PQR,AB=PQ,BC=QR and CB and who answer I mark that brainlist

Answer 1

In triangleABC & trianglePQR ,
AB=PQ & BC=QR
=> angleBCA=angleQRP ......[i] & angleBAC=angleQPR .....[ii]

Adding [i] & [ii] on both sides ,

angleBCA+angleBAC = angleQRP+angleQPR

=> angleABX = anglePQY.
=> 180degree - angleABX = 180degree -anglePQY
=> angleABC = anglePQR .......[iii]


In triangleABC and trianglePQR ,

AB=PQ [given]
angleABC = anglePQR [by (iii)]
BC=QR [given]

so, triangleABC is congruent to trianglePQR.
[by SAS-criterion]

Answer 2

:you can see the explanation which I have given in the photo.

Please mark it as brainiest.