Question

In triangle ABC and triangle PQR ,BC = QR angle A=90°,angle C = angle R=40° and angle Q = 50°​

Answer 1

Answer:

ANSWER

In ΔPQR 

∠R=40o,∠Q=50o ∠∠P+∠Q+∠R=180o[Sumofalltheanglesinatriangle=1800]

⇒∠P+50o+40o=180o

⇒∠P+90o=180o

⇒∠P=180o−90o

⇒∠P=90o

In ΔABC and ΔPQR

∠A=∠P

∠C=∠R

BC=QR

By Angle - Angle - Side crition of congruency , the triangle

ΔABC and ΔPQR are congruent to each other

∴ΔABC≅ΔPQR

Answer 2

Answer:

In ΔPQR

∠R=40

o

,∠Q=50

o

∠∠P+∠Q+∠R=180

o

[Sumofalltheanglesinatriangle=180

0

]

⇒∠P+50

o

+40

o

=180

o

⇒∠P+90

o

=180

o

⇒∠P=180

o

−90

o

⇒∠P=90

o

In ΔABC and ΔPQR

∠A=∠P

∠C=∠R

BC=QR

By Angle - Angle - Side crition of congruency , the triangle

ΔABC and ΔPQR are congruent to each other

∴ΔABC≅ΔPQR

solution