In triangle ABC and triangle PQR ,BC = QR angle A=90°,angle C = angle R=40° and angle Q = 50°
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In ΔPQR
∠R=40o,∠Q=50o ∠∠P+∠Q+∠R=180o[Sumofalltheanglesinatriangle=1800]
⇒∠P+50o+40o=180o
⇒∠P+90o=180o
⇒∠P=180o−90o
⇒∠P=90o
In ΔABC and ΔPQR
∠A=∠P
∠C=∠R
BC=QR
By Angle - Angle - Side crition of congruency , the triangle
ΔABC and ΔPQR are congruent to each other
∴ΔABC≅ΔPQR
Answered by
1
Answer:
In ΔPQR
∠R=40
o
,∠Q=50
o
∠∠P+∠Q+∠R=180
o
[Sumofalltheanglesinatriangle=180
0
]
⇒∠P+50
o
+40
o
=180
o
⇒∠P+90
o
=180
o
⇒∠P=180
o
−90
o
⇒∠P=90
o
In ΔABC and ΔPQR
∠A=∠P
∠C=∠R
BC=QR
By Angle - Angle - Side crition of congruency , the triangle
ΔABC and ΔPQR are congruent to each other
∴ΔABC≅ΔPQR
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