in triangle abc angel A =90 find the sin of B+C
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Answered by
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The sum of area in a triangle is 180°
Given that angle C is 90°
So, angle A+B = 180° - 90° = 90°
Sin(A+B) = Sin(90°) = 1 (ANSWER)
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Answered by
1
Answer:
A +B+C = 180*
90 + B+C= 180*
B+C= 180-90
B+C= 90
sin( B+C) = sin(90)
=1
I hope it may help you
thanks
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