Question

In triangle ABC ,angke b =90┬░ , BC=5cm, AC- AB=1cm . Evaluate 1+sin c/ cos c

Answer 1

hey there !!!

since AC - AB =1
           AC = 1+AB


so according to Pythagoras theorem,
 AC square = AB square + BC square

but since AC = 1+AB
So we can write
(1+AB)^2 + (AB)^2 + (5)^2

= 1+2AB=AB^2 = AB^2 = 25
= 1+2AB=25
=  2AB=24
=  AB=12 cm

Since AC=1+AB,
AC=13 cm

1+sinC/cosC

=1+12/13/5/13

= (13+12)/5
= 25/5
=5


therefore ans = 5

hope it helped you!!
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