Question

In triangle ABC, angle A=100 , AD bisects angle A and
AD is perpendicular to BC. Then angle B is equal to-​

Answer 1

Answer:

40°

Step-by-step explanation:

In ΔABC,

AD bisects angle A

So, angle BAD=angle CAD

angle A=100°

angle BAD=100°/2=50°

AD is perpendicular to BC

=angle ADB=90°

Thus,

angle BAD+ angle ADB +angle B=180°

=>50°+90°+angle B =180°

=>angle B=180°-140°=40°

<Please mark the answer as brainliest if it helps>