Question

In triangle abc , angle a=100 degree and ab=ac ,find angle b

Answer 1

HEY MATE ♡

HERE IS YOUR ANSWER

___________________

STEP BY STEP EXPLANATION:

Angle a=100°----(1.)

AB=AC

So, angle B=angleC -----(2.) (because angles opposite to equal sides are equal.)

Thus, by (1) and (2) we can conclude that

angle A+angleB+angleC=180°(Angle Sum Property)

so, 100+angleB+angleB=180

100+2(angle B)=180

2(angleB)=180-100

2(angle B)=80

angle B=80/2

angle B=40°

______________________☆☆

HOPE IT HELPED ^_^

Answer 2

$\texttt{\huge{Answer...}}$

The figure of the given situation is attached along with the answer.

Here, $\angle\: A=100°$
and AB = AC.

So, we can see that this triangle is an isosceles triangle. Thus, $\angle\: B = \angle\: C$. Let the measure of both the angles be x.

Now, applying $\textbf{Angle Sum Property}$ to ∆ABC,

$\angle\: A+\angle\: B+\angle\: C = 180°$

100° + x + x = 180°

2x = 180 - 100

2x = 80°

x = 40°

Thus, $\angle\: B=40°$

♥${Be}^{Brainly}$♥