Question

in triangle ABC angle a=2x-5, angle b=5x+5, angle c=3x+50,find the value of angle a,b,c,x

Answer 1

a = 2x-5

b = 5x+5

c = 3x + 50

a + b + c = 180

2x-5 + 5x + 5 + 3x +50 = 180

10x + 50 = 180

10x = 130

x = 13

a = 2*13 - 5 = 21

b = 5*13 +5 = 70

c = 3*13 +50 = 89

Answer 2

The angles A , B C and x are 21° , 60° , 89° and 13° respectively.

In a triangle ABC, ∠A = 2x - 5 , ∠B = 5x + 5 and ∠C = 3x + 50.

We have to find the value of angles A, B , C and x.

we know, sum of all angles of a triangle is 180°

∴ ∠A + ∠B + ∠C = 180°

⇒2x - 5° + 5x + 5° + 3x + 50° = 180°

⇒10x = 180° - 50° = 130°

⇒x = 13°

now, ∠A = 2x - 5° = 2 × 13° - 5° = 26° - 5° = 21°

∠B = 5x - 5° = 5 × 13° - 5° = 65° - 5° = 60°

∠C = 3x + 50° = 3 × 13° + 50° = 39° + 50° = 89°

∠x = 13°

Therefore the angles A , B C and x are 21° , 60° , 89° and 13° respectively.