Question

In triangle ABC angle A=30 ,angle angle B=90 find side AB if CA=10​

Answer 1

as it is a right angled triangle

CA^2 = AB^2 + BC^2

10^2 = AB^2 + BC^2

AB^2= 100-BC^2

AB = √(100-BC^2)

if BC value is given we can find the exact value of AB. maybe your question is incomplete.

Hope it helps you......

Answer 2

Step-by-step explanation:

just refer my attachment dr... hope helped ☺☺