In triangle ABC, angle A = 30,B = 40,C =110.The angles of the triangles formed by joining the mid points of the sides of this triangle are............................................................
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Answer :-
Given ,
In ∆ ABC
∠A = 30° , ∠B = 40° , ∠C = 110°
In Figure , BDEF , DCEF , DEAF are parallelogram So ,
∠B = ∠E = 40° [ ∠B & ∠E are opposite of parallelogram BDEF ]
∠C = ∠F = 110° [ ∠C & ∠F are opposite of parallelogram DCEF ]
∠A = ∠D = 30° [ ∠A & ∠D are opposite of parallelogram DEAF ]
Hence , ∠D = 30°
∠E = 40°
∠F = 110°
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