In triangle ABC angle A 40 degree and angle B 80 degree name its smallest side and its largest side .
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In triangle ABC
A=40°
B=80°
C=?
As we know sum of all side of a triangle is 180°
by Angle sum property.
A + B + C = 180° (A.S.P)
40° + 80° + C = 180°
120° + C = 180°
C = 180 - 120°
C = 60°
Largest side is "B" = 80°
Smallest side is "A" = 40°
A=40°
B=80°
C=?
As we know sum of all side of a triangle is 180°
by Angle sum property.
A + B + C = 180° (A.S.P)
40° + 80° + C = 180°
120° + C = 180°
C = 180 - 120°
C = 60°
Largest side is "B" = 80°
Smallest side is "A" = 40°
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Given:
Measurement of the given angle A = 40°
Measurement of the given angle B = 80°
To find:
The smallest and the largest side.
Solution:
First, let us find out the third angle (say ∠C) of the triangle. Since the sum of angles in a triangle is 180°, thus:
40° + 80° + C = 180°
120° + C = 180°
∠C = 60°
Since the largest angle is ∠B and the smallest angle is ∠A, thus the sides opposite to ∠B and ∠A will be the largest and the smallest sides respectively.
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