Question

in triangle ABC angle A=45° angle B=70° Then the shortest side of the triangle is​

Answer 1

Answer:

A is the shortest side

Step-by-step explanation:

A + B + C = 180° ( sum of the <s of a triangle is 180°)

45° + 70° + C = 180°

115° + C = 180°

C = 180° - 115°

C = 65°

<s is angles.

Answer 2

${\large \qquad \boxed{\boxed{\begin{array}{cc} \textsf{We have,} \\ \textsf{➸1st angle = 45°} \\ \textsf{➸2nd angle = 70°} \\ \textsf{➸3rd angle = ?} \\ \\ \large \textbf{So let's find the 3rd Angle} \\ \\ \sf{ \red➭ \angle A + \angle B + \angle C = 180 \degree} \\ \\ \sf{ \red➭ \angle 45 \degree+ \angle 70 \degree+ \angle C = 180 \degree} \\ \\ \sf{ \red➭ \angle C = 180 \degree - \angle 115 \degree} \\ \\ \dashrightarrow \underline {\boxed {\frak{ \pink{ \angle C = 65} }}}\bigstar \end{array}}}}$