in triangle ABC angle A=45degree,B=45degree and CD is the perpendicular from C to AB.CD =14 cm.calculate the length of AB
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Answer:
Given
C
D
⊥
A
B
,
∠
C
D
A
=
90
∘
In
Δ
A
D
C
,
s
i
n
45
∘
=
C
D
A
C
1
√
2
=
C
D
A
C
A
C
=
√
2
C
D
...(i)
Now, area of
△
A
B
C
=
1
2
×
A
B
×
C
D
⇒
40
c
m
2
=
1
2
×
20
×
C
D
⇒
C
D
=
4
c
m
On substituting the value of CD in equation (i), we get
A
C
=
√
2
×
4
=
4
√
2
c
m
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