In triangle abc angle a 50degree angle b 70 degree and bisector of angle C meets AB and D Find the measures of angle ACD and Angle ADC
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Step-by-step explanation:
In ∆ABC
Angle A = 50°
Angle B = 70°
Angle C = 180°-(50°+70°) = 180° - 130° = 50° .
Now,
As given in Question, D is the bisector if Angle C .
So,
Angle ADC = Angle ADB
Angle ADC+Angle ADB = 50° .
2(Angle ADC )= 50°
Angle ADC = 25° .
Angle ADB = 25° .
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