Question

In triangle ABC angle A=60, angle B=90 and angle C=30. If AB=√3 then find AC ?​

Answer 1

Step-by-step explanation:

In ∆ ABC , angle B=90° , angle C= 60° , angle A=30° and BC=12 cm. , applying

sine rule:-

AB/sinC = BC/sinA = CA/sinB.

or. AB/sin60° = 12/sin30°= CA/sin90°.

or. 2.AB/√3. = 2.12/1= CA/1.

or. AB = 12√3 cm. , CA(hypotenuse) = 24cm.

Area of triangle ABC = (1/2)×AB×BC = (1/2)× 12√3×12

= 72√3 cm^2. = 124.704 cm^2. Answer.

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Answer 2

Answer:

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