In triangle ABC , angle A =60 , angle C=40 and the bisector of angle ABC meets side AC at point P.Show that BP=CP
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acb = 40
bac = 60
.•. ABC = 80
BP bisects ABC
.•.pcb = 40
ACB = PCB =40...........proved
BP=CP ...,................converse of isoceles
∆ theorem
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