In triangle ABC angle A = 90, AB=3cm, BC=5 cm and AD perpendicular BC then the length of AD is-
a) 5/2 b)12/5 c) 5/12 d) (39^1/2)/2
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lengt of AD is = 1÷2 ×hypotenuse
= 1÷2 ×5
=5÷2 (a)
= 1÷2 ×5
=5÷2 (a)
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