in triangle abc angle a=90 ab=5cm ac=12 cm find sinB and tanC
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a=90 ab=5 ac=12cm
Step-by-step explanation:
bc^2 = 5^2 + 12^2
bc^2 = 25+144
bc^2 = 169
bc=√169
bc=13
sin b= p/h= 5/13
tan c= p/b=5/12
hope it helps !!!
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