Question

in triangle ABC;angle A=90 degrees, side AB = x cm, AC = (x+5) cm and area = 150 cm2. find the sides of the triangle​

Answer 1

Step-by-step explanation:

1/2*(x+5)*x=150

x^2+5x-300=0

x^2+20x-15x-300=0

x(x+20)-15(x+20)=0

(x-15)(x+20)=0

x=15

AB=15cm

AC=20cm

BC=√225+400=√625

BC=25cm