Question

in triangle ABC ,angle A=90, find tanB×tanC​

Answer 1

Answer:

Step-by-step explanation:

A = 90

A+B+C=180

90+B+C=180

B+C=90

B = 90-C

  tanB x tanC

= tan(90-C) x tanC                           tan(90-theta) = cot(theta)

=cotC x tanC                                     cot(a) = 1/tan(a)

= 1/tanC x tanC

= 1

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