Math, asked by rishwanthkumar10a1, 1 month ago

in triangle ABC Angle A = 90° AC = 8cm AB = 6cm find sin a and cos a​

plz explain step by step

Answers

Answered by emprodz2k19
0

Answer:

i dont know the answer.

Answered by jenwahlang533
2

Answer:

Since AB,BC and CA are tangents to the circle

⇒ OP,OM and ON are radius of the incircle

To find : radius 'r' of the incircle. ABC is a right angled triangleAB 2+AC 2

=BC 2 (Using pythagoras theorem)

⇒ (6) 2 +(8) 2

=BC 2

⇒ BC 2

=36+64

=100

⇒ BC= 100

=10cm

Since area of right anged triangle = 21×base×height

⇒ Area of △ABC= 21 ×6×8

=3×8=24cm 2

⇒ Area of △ABC=24cm 2....(1)

Also, Area of △ABC= area of △OAC+ area of △OBC+ area of △OBA

= 21×r×8+ 21 ×r×10+ 21×6×r

= 21 r(8+10+6)

= 21r(24)=12r....(2)

Equating (1) and (2) 12r=24

⇒ r= 1224

=2cm

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