in triangle ABC Angle A = 90° AC = 8cm AB = 6cm find sin a and cos a
plz explain step by step
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Since AB,BC and CA are tangents to the circle
⇒ OP,OM and ON are radius of the incircle
To find : radius 'r' of the incircle. ABC is a right angled triangleAB 2+AC 2
=BC 2 (Using pythagoras theorem)
⇒ (6) 2 +(8) 2
=BC 2
⇒ BC 2
=36+64
=100
⇒ BC= 100
=10cm
Since area of right anged triangle = 21×base×height
⇒ Area of △ABC= 21 ×6×8
=3×8=24cm 2
⇒ Area of △ABC=24cm 2....(1)
Also, Area of △ABC= area of △OAC+ area of △OBC+ area of △OBA
= 21×r×8+ 21 ×r×10+ 21×6×r
= 21 r(8+10+6)
= 21r(24)=12r....(2)
Equating (1) and (2) 12r=24
⇒ r= 1224
=2cm
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