In triangle ABC, angle A = 90°. AL is drawn perpendicular te the hypotenuse BC. Prove that angle BAL = angle ACB.
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Step-by-step explanation:
A triangle ABC is right-angled at A. AL is perpendicular on BC. How do you prove that <BAL = <ACB.
Triangle ABL and triangle ABC are similar as both are RATs. In triangle ABL, <BAL + <ABL = 90 deg. In triangle ABC, <ABC (which is same as <ABL) + <ACB = 90 deg. Hence <BAL + <ABL = <ABC (which is same as <ABL) + <ACB, therefore <BAL = <ACB. Proved.
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