In triangle ABC , angle A =90°. If AB =7 and BC -AC=1 cm, find : 1 )sin C
2)tan B
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In triangle abc angle is equal to 90
A B is equal to 7 cm
By Pythagoras theorem
(AB)²=(BC)² - (AC)²
49=(BC)²-(AC)²
By using the identity (a²-b²)=(a+b)(a-b)
49=(BC+AC)(BC-AC)
Since BC-AC=1
49=BC+AC
1=BC-AC
adding the two
50=2BC
BC=25
AC=24
Sin c=AB/BC
=7/25
And tan b =AB/AC
7/24=
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