Question

In triangle ABC,
angle A=90°. If AB =7 cm and BC-te
AC=1cm
find:
(i) Sin C
(ii) tan B​

Answer 1

Answer:

$\sin(c) = \frac{7}{ \sqrt{2} } \\ \tan(b ) = \frac{1}{7}$

Step-by-step explanation:

Here, A = 90°

AB = 7 cm

AC = 1 cm

Using Pythagoras theorem,

$ab^{2} + {ac}^{2} = bc^{2}$

$7^{2} + {1}^{2} = {bc}^{2} \\ \sqrt{49 + 1} = bc \\ bc = \sqrt{50} \\ bc = 5 \sqrt{2}$

Thus,

$\sin(c) = \frac{ab}{bc} \\ \sin(c) = \frac{7}{5 \sqrt{2} } \\ \tan(b) = \frac{ac}{ab} \\ \tan(b) = \frac{1}{7}$

Hope it helps you!!