in triangle ABC angle a+angle b=110degree and angle a+ angle c=132 degree find the value of angle a angle b, angle c
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a +b=110
b=110-a
a+c=132
c=132-a
a +b+c=180
a+110-a+132-a=180
242-180=a
a=62
b=48
c=70
b=110-a
a+c=132
c=132-a
a +b+c=180
a+110-a+132-a=180
242-180=a
a=62
b=48
c=70
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