In triangle ABC angle A=angle B =50°. Name the pair of side which are equal
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if angleA=angleB
Then sideAC will be equal to side BC
Then sideAC will be equal to side BC
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Given : Δ ABC ∠A =∠B = 50º
To Find : pair of sides which are equal .
Solution:
In a triangle sides opposite to equal angles are equal
Δ ABC ∠A =∠B = 50º
Side opposite to ∠A = BC
Side opposite to ∠B = AC
Hence BC = AC
Here AB is the base side of isosceles triangle and other two sides are equal
BC and AC are the sides which are equal
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