in triangle ABC , angle A +angle B = 80°and angle B +angle C =150° , find the measure of each angle of triangle ABC
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Let the angles of ∆ be ‹A , ‹B and ‹C
where, ‹A + ‹B +‹C = 180° ---------(1)
Now,
‹A + ‹B = 80°
‹B = 80°- ‹A ----------(2)
putting eqn (2) in (1) we get
<A + 80°-<A +<C = 180°
<C = 100°
Now A/Q
‹B + ‹C = 150°
‹B = 150° - ‹C ----------(3)
putting eqn (3) in (1) we get
<A + 150° - <C + <C = 180°
< A = 30°
remaining angle <B =
100° + 30° + < B = 180°
< B = 50°
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