In triangle abc angle a _ angle b equal 35 and angle b _ angle c equal 20 find all the angle of the triangle
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BC is a triangle. <A = 52 deg, <B = 58 deg, so < C = 180–52–58 = 70 deg. AB or
c = 20 cm
sin A/a = sin B/b = sin C/c, or
sin 52/a = sin 58/b = sin 70/20, or
a = 20xsin 52/ sin 70 = 16.77167057 cm
b = 20xsin 58/ sin 70 = 18.04947868 cm
So BC = 16.77167057 cm, AC = 18.04947868 cm and <C = 70 degrees.
c = 20 cm
sin A/a = sin B/b = sin C/c, or
sin 52/a = sin 58/b = sin 70/20, or
a = 20xsin 52/ sin 70 = 16.77167057 cm
b = 20xsin 58/ sin 70 = 18.04947868 cm
So BC = 16.77167057 cm, AC = 18.04947868 cm and <C = 70 degrees.
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