In triangle ABC, angle A=angle B. If AB square=2AC square, prove that ABC is right angled triangle.
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By pythagoras theorem of a²+b²=c² we can prove it. As A =B, we can safely arrive at conclusion that Sides opposite to these two Angles are equal So 2AC²=AB² means that this is right angle triangle
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A=B
which means BC=AC
AB^2=2AC^2......(given)
AB^2=AC^2+AC^2
AB^2=AC^2+BC^2
but this is Pythagoras theorem
therefore ∆ABC is right angled triangle with AB as hypotenuse
which means BC=AC
AB^2=2AC^2......(given)
AB^2=AC^2+AC^2
AB^2=AC^2+BC^2
but this is Pythagoras theorem
therefore ∆ABC is right angled triangle with AB as hypotenuse
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