In triangle ABC angle A- angleB=24° and angleB-angleC=30°.Find angle A.
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Answer:
∠A = 86°
Step-by-step explanation:
Given :
In △ABC,
∠A - ∠B = 24°
∠B - ∠C = 30°
To find : ∠A
Solution :
∠A - ∠B = 24°
∠A = 24° + ∠B -----> Equation 1
∠B - ∠C = 30°
∠B - 30° = ∠C -------------> Equation 2
Angle sum property of triangle:
∠A + ∠B + ∠C = 180°
(Now put the values of ∠A and ∠C from Equations 1 & 2)
24° + ∠B + (∠B + 30°) = 180°
3∠B - 6° = 180°
3∠B = 180° + 6°
3∠B = 186°
∠B = 186° \ 3
∠B = 62°
Put ∠B value in Equation 1
∠A = 24° + ∠B
∠A = 24° + 62°
∠A = 86°
Answer : Thus, ∠A = 86°
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