in triangle ABC, angle A exceeds angle B by 30 degree and angle B also exceeds angle C by 30 degree. Find the angles of the triangle
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Answer:
∠A = ∠B + 30
∠B = ∠C + 30
∠A = ∠C + 60
∠A+∠B∠C = 180
==> ∠C+∠C+30+∠C+30+30 = 180
==>3∠C+90 = 180
==> 3∠C = 90
==> ∠C = 30
Therefore;
∠C = 30
∠B = 30+30 = 60
∠A = 30+60 = 90
Step-by-step explanation:
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