Math, asked by pawani36, 2 months ago

In triangle ABC, angle A is 12x, angle B is 10x and angle C is 15x. Find angle A, B, C​

Answers

Answered by riyaz35
4

Step-by-step explanation:

ANGLE A + ANGEL B + ANGEL C = 180 ( ANGEL SUM PROPERTY OF A TRIANGLE )

12x +10x + 15x = 180

37x = 180

x= 180 ÷ 37

x = 0.2055

angle A = 12x = 12 ×0.2055= 2.466

angle B = 10x = 10 ×0.2055=2.055

angle C = 15x = 15 × 0.2055= 3.0825

Answered by ekampreetkaur12
1

Answer:

angle A=12x

angle B=10x

angle C=15x

Now,

In ∆ABC

angleA+angleB+angleC=180° (angle sum property)

12x+10x+15x=180°

37x= 180°

x=180/37

x= 4.86° (approx.)

angleA= 12x = 12*4.86

= 58.82°

angleB= 10x = 10*4.86

=48.6°

angleC= 15x = 15*4.86

= 72.9°

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