Question

in triangle abc , angle a is 70 degree & ad is perpendicular bc . if angle c is 50 degree find angle DAC & angle ABC​

Answer 1

Given

Angle A=70°

AD Perpendicular BC.

So Angle ADC and ADB=90°

Also,AngleC=50°

In ∆ADC.

By angle sum Prpty of a Triangle...

180°=dac+adc+acd

→180°=50°+90°+dac

→Angle dac=180°-140°=40°.

Given,AngleA=70°

But angle A=dac+dab

→70°=40°+dab

→angle DAB=70-40=30°

in ∆DAB.

By angle Sum Prptg of a Triangle.

180°=dab+adb+abd

→Angle ABD=180°-(30°+90°)=180°-120°=60°

→Angle ABC=60° (angle abc is same as angle abd)

So angle DAC=40°

And angle ABC=60°

Hope It helps...

Answer 2

Answer:

angle DAC + angle ACD + angle CDA = 180° (sum of all angles of triangle)

angle DAC + 50° + 90° = 180°

[[[[[Angle DAC = 40°]]]]]]

Now Angle AbC + angle BCA + CAB = 180°

Angle ABC + 50° + 70° = 180°

[[[angle ABC = 60°]]]]

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