Question

In triangle ABC angle A is equal to angle C and BM bisect triangle ABC prove that BMis perpendiculer to AC

Answer 1

Here, in ∆ABC.

angle A = angle B

therefore, it is an isosceles ∆triangle.
and in an isosceles ∆ ,the sides opposite to the equal angles are equal..
i.e. AB=BC

if BM bisect ∆ABC .°.

in ∆BMC and ∆BMA,

BM=BM. ----1

ANGLE A = ANGLE C. ----2

and,AB=BC

Hence, ∆BMA =~ ∆BMC..

proved...

try and practice,it will help you you

Answer 2

Answer-bm perpendicular to ac

Explanation:Angle a=angle c(given),

Angle ABM =angle CBM (given)

BM=BM(common);triangle ABM