Question

in triangle abc angle A is equals to 90 degree if a b is equals to 7 cm and BC minus AC is equals to 1 cm find sin c number 2 tan b​

Answer 1

let BC =x

and AC=y

according to question BC-AC=1

=》》x-y=1

using pythagoras formula

BC^2=AC^2+AB^2

=》》x^2=49+y^2

from above relations

x^2=49+(x-1)^2

x^2=49+x^2+1-2x

2x=50

x=25

=》》y=24

now sinC=AB/BC

sinC=7/25

TanB=AC/AB

tanB=24/25

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Answer 2

Step-by-step explanation:

Let BC and AC be x cm and y cm respectively

given : BC - AC = 1 cm

Therefore, x - y = 1 cm

=>x - 1 = y cm

H² = P² + B²

=>BC²= AB² + AC²

=>x². =7² +y²

=>x² = 49+y²

=>x²= 49+(x-1)². (since,value of y = x-1)

=>x²=49+x² - 2x +1

=>x² -x² +2x= 50

=>2x = 50

=>x = 50/2= 25cm

Therefore, x - 1 = ycm

so 25 - 1 = 24 cm

BC = x = 25cm, AC = y = 24cm

i) Sin C = Perpendicular/Hypotenuse

= AB/BC

= 7/25 ans.

ii) Tan B = Perpendicular/Base

= AC/AB

= 24/7 ans.

(just for knowledge - the part which contain both the angle and perpendicular (90°) is known as base.)