in triangle abc angle A minus angle b is equal to 30 degree angle B minus angle C is equal to 15 degree find the measure of Angle B
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Given Angle A-Angle B=30°_______(1)
Also Angle B-Angle C=15°________(2)
Now also from eqn1 we get Angle A=30°+Angle B. Also from eqn2 we get Angle C=Angle B-15°
Now as ABC IS A TRIANGLE therefore by applying angle sum property we have Angle A+Angle B+Angle C=180°
Now (30+AngleB )+(Angle B)+(AngleB-15)=180°
3×Angle B=180°-15°
Angle B=165°/3
Angle B=55° Ans
Also Angle B-Angle C=15°________(2)
Now also from eqn1 we get Angle A=30°+Angle B. Also from eqn2 we get Angle C=Angle B-15°
Now as ABC IS A TRIANGLE therefore by applying angle sum property we have Angle A+Angle B+Angle C=180°
Now (30+AngleB )+(Angle B)+(AngleB-15)=180°
3×Angle B=180°-15°
Angle B=165°/3
Angle B=55° Ans
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