Question

in triangle abc angle A minus Angle B is equals to 63 degree, angle B minus angle C is equals to 18 degree find the measurement of Angle B

Answer 1

Answer:

In ∆ABC, we have

$\angle$A + $\angle$B + $\angle$C = 180°...........(1)

It is given that

$\angle$A - $\angle$B = 63°

$\rightarrow$ $\angle$A = $\angle$B + 63°...........(2)

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and $\angle$B - $\angle$C = 18°

$\rightarrow$ $\angle$C = $\angle$B - 18°.............(3)

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From (1), (2) and (3) we get,

($\angle$B + 63°) + $\angle$B + ($\angle$B - 18°) = 180°

$\implies$3$\angle$B + 63° - 18° = 180°

$\implies$3$\angle$B + 45° = 180°

$\implies$3$\angle$B = 180° - 45°

$\implies$3$\angle$B = 135°

$\implies$$\angle$B = $\sf\frac{135°}{3}=45°$

Answer 2

Answer:

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