Math, asked by nitinthecursor7729, 1 year ago

In triangle ABC angle a os acute. BD and CE are perpendicular on AC and AB respectively. Prove AB x AE = AC x AD

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Answered by Elwin123
101


In △ ADB and △ AEC∠A = ∠A   [Common]∠ADB = ∠AEC   [Each 90°]∴ △ADB ~ △ AEC    [AA − Similarity]then, ADAE = ABAC    [Corresponding sides of 2 similartriangles are proportional]⇒ AB × AE = AC × AD                HENCE PROVED

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Answered by am3107
56
I am solve your problem and I hope you can help for this answer
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