in triangle abc angle A=theta and angle b =90 and angleC=theta if BC=x and AC= X + 2 find the value of root under x + 1 cot theta
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4
Answer:
ANSWER
AB : AC = 1 :
2
⇒
AC
AB
=
2
1
∴ AB = x and AC =
2
x, for some x.
By Pythagoras theorem, we have
AC
2
=AB
2
+BC
2
⇒(
2
x)
2
=x
2
+BC
2
⇒BC
2
=2x
2
−x
2
=x
2
⇒BC=x
∴tanA=
AB
BC
=
x
x
=1
we have,
1+tan
2
A
tanA
=
1+1
2
1
=
2
1
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10
Answer:
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