in triangle ABC, angle a= x degree , angle b=3x , angle c= y degree . If 3y-5x=30,prove that the triangle is a right triangle
Answers
Answered by
399
∠A+∠B+∠C= 180°
x+3x+y=180°
4x+y=180°
operating 3×4x+y-3y-5x=3×180-30°
12x+5x=540°-30°
17x=510°
x=30°
∠A=30
∴∠B=3x=3×30=90
HENCE IT IS A RIGHT ANGLE
x+3x+y=180°
4x+y=180°
operating 3×4x+y-3y-5x=3×180-30°
12x+5x=540°-30°
17x=510°
x=30°
∠A=30
∴∠B=3x=3×30=90
HENCE IT IS A RIGHT ANGLE
Answered by
179
Answer:
The given triangle is a right angled triangle as it contains one of its angle as 90°
Solution:
We know that sum of all the angles of a triangle = 180°
Here
Thus,
Given,
Hence, to put the value of 3° in equation (i), multiply equation (i) by 3 on both the sides
∴ The three angles of the triangle are:
Here, one of the angle of the triangle is 90°. Hence, the given triangle is a right angled triangle.
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