In triangle ,ABC angle A = x° , angle B =3x° , and angle C=y° if (3y-5x)=30 .Show that the triangle is right angled
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3x is going to be 90 and complete proving is in this page
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sum of internal angles in a triangle=180°
so A+B+C=180°
x+3x+y=180°
4x+y=180°
y=180°-4x --------------->(1)
but given 3y-5x=30 ------------>(2)
so by keeping (1) in (2),
3*(180-4x)-5x=30
540-17x=30
17x=510
x=30, now y=180-4*30=60
so A=30°, B=90° ,C=60°
clearly it is a right - angled triangle
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